4. Se desea conocer la actitud del estudiante sobre los cursos de verano. Sabiendo que hay 2312 estudiantes inscritos y un error de estimacion de 5%. Calcule "n" para Z=1,2 y 3.

1- N= 2312

    2- E= 5%

    3- Z=1, 2, 3

    4- p= 0,5

    5- q= 0,5                                    1)

                                                           n=              0,5.0,5.2312.1²

                                                                 __________________________

                                                                     (0,05)².(2312-1)+1².0,5.0,5

                                                           n=                     578

                                                                   _____________________

                                                                       0,0025 (2312-1)+0,25

                                                           n=                     578

                                                                   ______________________

                                                                              5,7775+0,25

                                                          

                                                            n=                 578

                                                                   __________________  = 95,8

                                                                               6,0275

                                                            n1= 96

    1- N= 2312

    2- E= 5%

    3- Z=1, 2, 3

    4- p= 0,5

    5- q= 0,5                                      2)                     

                                                           n=              0,5.0,5.2312.2²

                                                                 __________________________

                                                                     (0,05)².(2312-1)+2².0,5.0,5

                                                           n=                    2312

                                                                   _____________________

                                                                        0,0025 (2312-1)+1

                                                           n=                    2312

                                                                   ______________________

                                                                                5,7775+1

                                                          

                                                            n=                2312

                                                                   __________________

                                                                               6,7775

                                                            n2= 341

    1- N= 2312

    2- E= 5%

    3- Z=1, 2, 3

    4- p= 0,5

    5- q= 0,5                                          3)                

                                                           n=              0,5.0,5.2312.1²

                                                                 __________________________

                                                                     (0,05)².(2312-1)+3².0,5.0,5

                                                           n=                     5202

                                                                   _____________________

                                                                       0,0025 (2312-1)+2,25

                                                           n=                     5202

                                                                   ______________________

                                                                              5,7775+2,25

                                                          

                                                            n=                 5202

                                                                   __________________

                                                                               8,0275

                                                            n3= 648

5.  Imagínese una firma industrial comprometida en la producción de artículos metálicos para la industria espacial. Entre sus productos hay tornillos para los cuales existen estrechos margenes de tolerancia respecto a la anchura. Como una parte de los controles de calidad, se selecciona cierto numero de tornillos de la producción diaria, la cual es de 5000 tornillos. Calcule el tamaño de la muestra con un error del 5% para Z=2.



    1- N= 5000

    2- E= 3, 5%

    3- Z= 3

    4- p= 0,5

    5- q= 0,5                                                          

                                                           n=              0,5.0,5.5000.3²

                                                                 __________________________

                                                                     (0,04)².(5000-1)+3².0,5.0,5

                                                           n=                     11250

                                                                   _____________________

                                                                       0,0016 (5000-1)+2,25

                                                           n=                     11250

                                                                   ______________________

                                                                               7,9984+2,25

                                                           

                                                            n=                 11250

                                                                   __________________  = 1071,5

                                                                               10,4984

                                                            n= 1072





6. Se quiere conocer la importancia del Deporte en el Desarrollo Integral del Adolescente maracaibero. Si existen 4321 técnicos participando en los JUVINES LUZ. Calcule el tamaño de la muestra con un error del 5% para Z=2.

    1- N= 4321

    2- E= 5%

    3- Z= 2

    4- p= 0,5

    5- q= 0,5                                                            

                                                           n=              0,5.0,5.4321.2²

                                                                 __________________________

                                                                     (0,05)².(4321-1)+2².0,5.0,5

                                                           n=                     4321

                                                                   _____________________

                                                                       0,0025 (4321-1)+1

                                                           n=                     4321

                                                                   ______________________

                                                                                   10,8+1

                                                          

                                                            n=                 4321

                                                                   __________________

                                                                                  11,8

                                                            n= 366

7. Se desea conocer la proporción de niños que nacen con malformaciones entre todos los recién nacidos de la ciudad de Maracaibo. si de los 5 hospitales los niños nacidos este año son 3245, que muestra debe tomarse con un error del 2% y nivel de confianza del 99,7%.

    1- N= 3245

    2- E= 2%

    3- Z= 99,7%

    4- p= 0,5

    5- q= 0,5                                                           

                                                           n=              0,5.0,5.3245.3²

                                                                 __________________________

                                                                     (0,02)².(3245-1)+3².0,5.0,5

                                                           n=                   7301,25

                                                                   _____________________

                                                                       0,0004 (3245-1)+2,25

                                                           n=                     7301,25

                                                                   ______________________

                                                                                   1.298+2,25

                                                          

                                                            n=                 7301,25

                                                                   __________________  = 2057,8

                                                                                  3.548

                                                            n= 2058